0=-15.90x^2+110.48x-2.98

Solution for 0=-15.90x^2+110.48x-2.98 equation:

0=-15.90x^2+110.48x-2.98

We move all terms to the left:

0-(-15.90x^2+110.48x-2.98)=0

We add all the numbers together, and all the variables

-(-15.90x^2+110.48x-2.98)=0

We get rid of parentheses

15.90x^2-110.48x+2.98=0

a = 15.90; b = -110.48; c = +2.98;
Δ = b2-4ac
Δ = -110.482-4·15.90·2.98
Δ = 12016.3024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-110.48)-\sqrt{12016.3024}}{2*15.90}=\frac{110.48-\sqrt{12016.3024}}{31.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-110.48)+\sqrt{12016.3024}}{2*15.90}=\frac{110.48+\sqrt{12016.3024}}{31.8}
$